Practice exam #1:
Here's the story: Your dog, Momo, barks way
too much and you can't figure out why. One day, you
forget to give Momo doggie biscuits and you notice that she does not
bark that day. After thinking about this issue for
a bit, you decide to run a study using 3 other dogs to determine
whether # of doggie biscuits consumed is indeed related to the amount
of barking. In this study you measure (X) the
number of doggie biscuits each dog eats in a day and (Y) the number of
times that dog barks, in order to see what the actual relationship is
between these two variables.
X (# of
doggie biscuits consumed) Y
(# of barks in a day)
0
2
1
1
2
3
1. Create
a frequency table for X.
2. Create
a frequency histogram for X.
3. Compute
the following:
Mean for X:
Mean for Y:
Median for X:
Median for Y:
Mode for X:
Mode for Y:
SSx:
SSy:
SDx2:
SDy2:
SDx:
SDy:
4. What
is Zx when X = 0?
5. If
Zy = 1.4, what would be the corresponding Y value?
6. What
is the sum of the cross product of Z scores between X and Y?
7. What
is the correlation (r) between X and Y?
8. Write
the Z-score prediction model to predict Zy from Zx.
9. What
is the predicted Zy if Zx = 0?
10. Write the
raw-score prediction model to predict Y from X.
11. Draw
scatterplot of raw data showing the correlation between X and Y.
12. The
scatterplot shows that the relationship between X and Y is
A. very
strong and positive.
B. very
strong and negative.
C. moderate
and positive.
D. moderate
and negative.
13. Draw
the regression line on the scatterplot up above.
14. Compute
the proportionate reduction of error (NOT by just squaring "r").
15. Based
on the proportionate reduction of error, what would you conclude about
how well X predicts Y? EXPLAIN.
ANSWER KEY:
X
-
M (X-M)
(X-M) 2
Zx
0
-
1 -1
1
-1.22
1
-
1 0
0
0
2
-
1 1
1
1.22
___________________________________
Mx = 1
SSx = 2
SDx2 = .67
SDx = .82
Y
-
M (Y-M)
(Y-M) 2
Zy
2
-
2 0
0
0
1
-
2 -1
1
-1.22
3
-
2 1
1
1.22
___________________________________
My = 2
SSy = 2
SDy2 = .67
SDy = .82
ZxZy
-1.22*0
= 0
0*-1.22
= 0
1.22*1.22=
1.49
___________________
S(ZxZy) = 1.49
r = 1.45/3 = .50
Z score
model ---->
Zy(hat) = (.50)(Zx)
Raw score model ---->
b = .50(.82/.82) =
.50
a = 2 - (1)(.50) =
1.50
----> Y` = 1.50 + .50(X)
Zy (predicted) if Zx = 0 ... Zy = 0
r2 = (SSt - SSe)/SSt ...
Error
Error2
Y
Y`
(Y- Y`)
(Y- Y`)2
2
1.50
.50
.25
1
2
-1
1
3
2.50
.50
.25
____________________________________________
SSe = S(Y- Y`)2 = 1.5
-- SSt = SSy = 2
r2 =
(SSt - SSe)/SSt = (2-1.5)/2 = .5/2 = 1/2*1/2 = .25
(r2 = .50*.50 = .25)